-5x^2-4x+36=0

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Solution for -5x^2-4x+36=0 equation:



-5x^2-4x+36=0
a = -5; b = -4; c = +36;
Δ = b2-4ac
Δ = -42-4·(-5)·36
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{46}}{2*-5}=\frac{4-4\sqrt{46}}{-10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{46}}{2*-5}=\frac{4+4\sqrt{46}}{-10} $

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